1828 United States presidential election in Georgia

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1828 United States presidential election in Georgia
Flag of the State of Georgia (non-official).svg
← 1824 October 31 – December 2, 1828 1832 →
  Andrew Jackson.jpg John Quincy Adams 1858 crop.jpg
Nominee Andrew Jackson John Quincy Adams
Party Democratic National Republican
Home state Tennessee Massachusetts
Running mate John C. Calhoun Richard Rush
Electoral vote 9 0
Popular vote 19,362 642
Percentage 96.79% 3.21%

In the 1828 United States presidential election, Georgia voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Georgia by a margin of 93.58%.

Seven Georgian electors voted for William Smith for vice president, rather than Jackson's official running mate, John C. Calhoun.[1]

Results[]

United States presidential election in Georgia, 1828[2]
Party Candidate Votes Percentage Electoral votes
Democratic Andrew Jackson 19,362 96.79% 9
National Republican John Quincy Adams 642 3.21% 0
Totals 20,004 100.0% 9

References[]

  1. ^ "Electoral Votes for President and Vice President, 1821-1837 – 1828 Election for the Eleventh Term". National Archives and Records Administration. Retrieved 6 September 2018.
  2. ^ "1828 Presidential General Election Results - Georgia". U.S. Election Atlas. Retrieved 28 February 2013.


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