1880 United States presidential election in Delaware

1880 United States presidential election in Delaware

← 1876 November 2, 1880 1884 →

Nominee Winfield S. Hancock James A. Garfield Party Democratic Republican Home state Pennsylvania Ohio Running mate William H. English Chester A. Arthur Electoral vote 3 0 Popular vote 15,181 14,148 Percentage 51.53% 48.03%

County Results Hancock   50-60% Garfield   50-60%

President before election Rutherford B. Hayes Republican Elected President James Garfield Republican

Elections in Delaware
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Wilmington Mayoral elections 2012 2016 2020
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The 1880 United States presidential election in Delaware took place on November 2, 1880, as part of the 1880 United States presidential election. State voters chose three representatives, or electors, to the Electoral College, who voted for president and vice president.^[1]

Delaware was won by General Winfield Scott Hancock (D–Pennsylvania), running with former Representative William Hayden English, with 51.53% of the popular vote, against Representative James A. Garfield (R-Ohio), running with the 10th chairman of the New York State Republican Executive Committee Chester A. Arthur, with 48.03% of the vote.^[1]

Results[]

See also[]

• United States presidential elections in Delaware

References[]

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