Luze, Haute-Saône

From Wikipedia, the free encyclopedia
Luze
Commune
The town hall in Luze
The town hall in Luze
Coat of arms of Luze
Coat of arms
Location of Luze
Luze is located in France
Luze
Luze
Coordinates: 47°35′52″N 6°44′25″E / 47.5978°N 6.7403°E / 47.5978; 6.7403Coordinates: 47°35′52″N 6°44′25″E / 47.5978°N 6.7403°E / 47.5978; 6.7403
CountryFrance
RegionBourgogne-Franche-Comté
DepartmentHaute-Saône
ArrondissementLure
CantonHéricourt-1
IntercommunalityCC pays d'Héricourt
Government
 • Mayor (2020–2026) Éric Steib
Area
1
10.69 km2 (4.13 sq mi)
Population
 (Jan. 2018)[1]
733
 • Density69/km2 (180/sq mi)
Time zoneUTC+01:00 (CET)
 • Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
70312 /70400
Elevation330–531 m (1,083–1,742 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Luze (French pronunciation: ​[lyz]) is a commune in the Haute-Saône department in the region of Bourgogne-Franche-Comté in eastern France.

See also[]

References[]

  1. ^ "Populations légales 2018". INSEE. 28 December 2020.



Stub icon

This Haute-Saône geographical article is a stub. You can help Wikipedia by .

Retrieved from ""