2019 St. Petersburg Open – Doubles

Doubles
2019 St. Petersburg Open
Champions	Divij Sharan Igor Zelenay
Runners-up	Matteo Berrettini Simone Bolelli
Final score	6–3, 3–6, [10–8]
Events
Singles Doubles
← 2018 · St. Petersburg Open · 2020 →

Matteo Berrettini and Fabio Fognini were the defending champions,^[1] but Fognini chose not to participate this year. Berrettini played alongside Simone Bolelli, but lost in the final to Divij Sharan and Igor Zelenay, 3–6, 6–3, [8–10].

Seeds[]

Draw[]

Key[]

Draw[]

	First Round							Quarterfinals							Semifinals							Final
	1	N Mektić F Škugor	6	6
	PR	R Berankis J Tipsarević	3	4				1	N Mektić F Škugor	6	6
		N Monroe A Vasilevski	6	6					N Monroe A Vasilevski	4	2
	WC	E Donskoy K Kravchuk	3	2											1	N Mektić F Škugor	5	1
	4	M Demoliner M Middelkoop	6	2	[5]											D Sharan I Zelenay	7	6
		D Sharan I Zelenay	3	6	[10]				D Sharan I Zelenay	7	5	[10]
	WC	E Karlovskiy A Rublev	77	2	[2]				R Carballés Baena A Molteni	5	7	[5]
		R Carballés Baena A Molteni	65	6	[10]																		D Sharan I Zelenay	6	3	[10]
		F Nielsen T Pütz	6	6																			M Berrettini S Bolelli	3	6	[8]
		M Fucsovics S Travaglia	4	4					F Nielsen T Pütz	4	6	[7]
		M Berrettini S Bolelli	6	6					M Berrettini S Bolelli	6	4	[10]
	3	R Jebavý P Oswald	2	2												M Berrettini S Bolelli	7	7
		A Bublik M Kukushkin	64	3											2	S Gillé J Vliegen	5	5
		A Mannarino H Nys	77	6					A Mannarino H Nys	4	4
	PR	J Kovalík H Podlipnik Castillo	4	4				2	S Gillé J Vliegen	6	6
	2	S Gillé J Vliegen	6	6

References[]

• Main Draw