Montpeyroux, Dordogne

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Montpeyroux
The church in Montpeyroux
The church in Montpeyroux
Coat of arms of Montpeyroux
Location of Montpeyroux
Montpeyroux is located in France
Montpeyroux
Montpeyroux
Coordinates: 44°55′16″N 0°03′28″E / 44.9211°N 0.0578°E / 44.9211; 0.0578Coordinates: 44°55′16″N 0°03′28″E / 44.9211°N 0.0578°E / 44.9211; 0.0578
CountryFrance
RegionNouvelle-Aquitaine
DepartmentDordogne
ArrondissementBergerac
CantonPays de Montaigne et Gurson
Government
 • Mayor (2020–2026) Christophe Marceteau
Area
1
23.37 km2 (9.02 sq mi)
Population
 (Jan. 2018)[1]
451
 • Density19/km2 (50/sq mi)
Time zoneUTC+01:00 (CET)
 • Summer (DST)UTC+02:00 (CEST)
INSEE/Postal code
24292 /24610
Elevation17–100 m (56–328 ft)
(avg. 100 m or 330 ft)
1 French Land Register data, which excludes lakes, ponds, glaciers > 1 km2 (0.386 sq mi or 247 acres) and river estuaries.

Montpeyroux (French pronunciation: ​[mɔ̃peʁu]; Occitan: Montpeirós) is a commune in the Dordogne department in Nouvelle-Aquitaine in southwestern France.

Population[]

Historical population
YearPop.±%
1962514—    
1968452−12.1%
1975359−20.6%
1982318−11.4%
1990338+6.3%
1999360+6.5%
2008424+17.8%

See also[]

References[]

  1. ^ "Populations légales 2018". INSEE. 28 December 2020.


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